micropython/tests/basics/fun-kwonly.py
Damien George f0778a7ccb py: Implement default keyword only args.
Should finish addressing issue #524.
2014-06-07 22:01:00 +01:00

69 lines
875 B
Python

# to test keyword-only arguments
# simplest case
def f(*, a):
print(a)
f(a=1)
# with 2 keyword-only args
def f(*, a, b):
print(a, b)
f(a=1, b=2)
f(b=1, a=2)
# positional followed by bare star
def f(a, *, b, c):
print(a, b, c)
f(1, b=3, c=4)
f(1, c=3, b=4)
f(1, **{'b':'3', 'c':4})
try:
f(1)
except TypeError:
print("TypeError")
try:
f(1, b=2)
except TypeError:
print("TypeError")
try:
f(1, c=2)
except TypeError:
print("TypeError")
# with **kw
def f(a, *, b, **kw):
print(a, b, kw)
f(1, b=2)
f(1, b=2, c=3)
# with a default value
def g(a, *, b=2, c):
print(a, b, c)
g(1, c=3)
g(1, b=3, c=4)
g(1, **{'c':3})
g(1, **{'b':'3', 'c':4})
# with named star
def f(*a, b, c):
print(a, b, c)
f(b=1, c=2)
f(c=1, b=2)
# with positional and named star
def f(a, *b, c):
print(a, b, c)
f(1, c=2)
f(1, 2, c=3)
f(a=1, c=3)