import io
import sys

sys.stdin = io.StringIO('3')  # 9
sys.stdin = io.StringIO('2022')  # 593300958

# from itertools import permutations
#
# per = list(permutations(range(5)))
# print(per)
# 冒泡的交换次数公式
# print(len(per))

n = int(input())
ans = 0
per_num = 1
for i in range(1, n + 1):
    for p in range(2, i + 1):
        per_num *= p
        ans += per_num // 2
        ans %= 998244353

print(ans)