add 电信研发工程师考试内容.

ct/l1/8-平衡数.py

@@ -0,0 +1,17 @@
+def f(x):
+    y = 1
+    for j in x:
+        y *= int(j)
+    return y
+
+
+n = input()
+flag = True
+for i in range(1, len(n)):
+    left, right = n[:i], n[i:]
+    if f(left) == f(right):
+        flag = False
+        print("YES")
+        break
+if flag:
+    print("No")